what is the relation between the co-effitients if the pair of linear equations px-qy+r=0 and sx+Ty-u=0 is inconsistent
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Answer:
p/s = -q/t ≠ -r/u
Step-by-step explanation:
if the equations are inconsistent then a1 / a2 = b1 / b2 ≠c1 / c2
⇒ a1 = p , a2 = s , b1 = -q , b2 = t , c1 = r , c2 = -u
⇒ p/s = -q/t ≠ -r/u
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