Question

What is the remainder if face value of a digit at the lakh place is subtracted from the place value of digit at lakh place in the smallest 6 digit number formed by using all digits other than 0,2,5

Answer 1

Answer:

1,99,998

Step-by-step explanation:

first form 6 digit smallest no by using given no

so it is 2,00,005

Now face value and place value of lakhs place is 2 and 2,00,000

and final subtract 200000-2=1,99,998.

Answer 2

The remainder is 99999

Step-by-step explanation:

The smallest 6 digit number formed by digits other than 0,2,5  is

134678

then ,

face value of the digit at lakhs place = 1

place value of the digit at lakhs place = 100000

then

their difference = place value - face value

= 100000 - 1

= 99999

hence , The remainder is 99999

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