What is the remainder of ( 4׳ + ײ - 6× + 2 ) ÷ ( × - 1 )?
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put 1 in all places where x is there you have it
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Aɴsᴡᴇʀ:-
( 4׳ + ײ - 6× + 2 ) ÷ ( × - 1 )
P ( x ) = P ( 1 )
P ( 1 ) = 4 ( 1 ) ² + ( 1 ) ² - 6 ( 1 ) + 3
P ( 1 ) = 4 + 1 - 6 + 3
P ( 1 ) = 2
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