Question

What is the remainder when 101102103104105106107........148149150 divided by 9?

Answer 1

Answer:

2

Step-by-step explanation:

101102103.............148149150

Total account for 50 numbers and each number has 3 digits. Therefore, in total there are 3*50= 150 digits

Now of sum of digits = 101+102+.......150

= 50×(101+150)/2= 6275

further the sum of digit = 6+2+7+5= 20

20 = 2(Mod 9)

therefore, remainder would be 2