what is the remainder when 10x^159-5 is divided by (x-1)? show solution pls
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Answer:
The polynomial remainder theorem says that when f(x) is divided by (x−a),
the remainder is given by f(a).
Here, f(x)=x5+1 and it is divided by (x−2)
∴a=2
∴Remainder=f(2)=25+1=33
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