what is the remainder when 2^57 is divided by 3
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we know
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64
2^7 = 128
2^8 = 256
2^9 = 512
Thus we can get that
last digit of 2 ^57 will be 8
thus dividing 8 by 3
we get remainder = 2
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64
2^7 = 128
2^8 = 256
2^9 = 512
Thus we can get that
last digit of 2 ^57 will be 8
thus dividing 8 by 3
we get remainder = 2
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