what is the remainder when 73^382 is divided by 100
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Answer:
73^382
= (73^4)^95 × 73^2
(73^2 × 73^2)^95 × 73^2
(29×29)^95 × 73^2
(41^95) × 73^2
01 × 29
= 29/100
Rem = 29
hope it helps you....
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