what is the remainder when x^3+3x^2+3x+1 is divided by x-1/2
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2
Answer:
answer for the given problem is given
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Answered by
2
Answer:
27 / 8
Step-by-step explanation:
given polynomial is p(x) = x^3+3x^2+3x+1
=> p(x) = x³ + 3x² + 3x + 1
given, p(x) is divided by x-1/2
=> remainder = p(½)
= (½)³ + 3(½)² + 3(½) + 1
= 1/8 + 3(1/4) + 3/2 + 1
= 1+6+12+8 / 8
=> remainder = 27 / 8
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