Question

what is the resistance of a 1000 watts and 210 volts heater​

Answer 1

As given in question :

P= 1000 watt ( assumed that temprature remain constant)

V= 250 V so, I ( current) = P÷V = 1000÷250 = 4 Amperes.

And power dissipation 1000 watt = I^2R that is 4×4×R or R = 1000÷16 = 62.5 ohms (at constant temprature).

If we consider that temprature is constant,

The power dissipation for applied 200 V will be V^2 ÷R or 200×200/ 62.5 = 40000÷62.5 = 640 watt. It's a theoretical explanation.

Answer 2

Answer:

44ohm

Explanation:

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