Question

what is the resistance of the coil whose time constant is 2 and value of its inductor is 15 henry​

Answer 1

Answer:

Time constant in LR circuit = inductance /resistance

Therefore,

Resistance = inductance /time constant

=15/2

=7.5

Answer 2

Concept:

The duration necessary for the circuit to achieve 63 per cent of the final value is the time constant (steady-state value).

It is mathematically expressed as Time constant = Induction/Resistance

Given:

Time constant = 2

Induction of coil = 15 henry

Find:

We need to determine the resistance, R of the coil

Solution:

The duration necessary for the circuit to achieve 63 per cent of the final value is the time constant (steady-state value).

It is formulated as- Time constant = Induction/Resistance

t = L/R where L is the Induction and R is the resistance

Electromagnetic induction, or simply induction, creates an electrical current in a conductor by exposing the conductor to a fluctuating magnetic field. Because the magnetic field is thought to have induced the current in the conductor, it is known as induction and the obstruction to current flow in an electrical circuit is measured by resistance.

We have, t = 2 and L = 15 henry

Therefore, t = L/R becomes

2 = 15/R

Therefore, R = 15/2

R = 7.5 ohm

Thus, the resistance, R of the coil is 7.5 ohm

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