What is the result a2+bc-ba-ac
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Step-by-step explanation:
a² + bc + ab + ac
rearrangeing the terms , we get
=a² + ab + ac + bc
=(a×a+a×b) + (a×c+b×c)
■ take a & c common in first & second brackets respectively, we get
= a (a + b ) + c (a + b)
■again take (a+b)
■ common, we get
= (a+b) (a+c)
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