Computer Science, asked by Mohith2008, 19 days ago

What is the result stored in x , after evaluating the following expression

int x=8;
x=x++*2+3*--x​

Answers

Answered by chauhanchandrika90
0

Answer:

25

Explanation:

x++ in equation in gonna be x only for the x++*2 part hence 5*2+3*--x 10+3(5+1-1) 10+3*5 10+15 25

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