Question

What is the retardation if a car moving with a velocity of 50 km/hr is brought to rest in 45 sec ?

Answer 1

here is your answer hope it will help you

Answer 2

Answer:

Step-by-step explanation:

Given: u=$50\frac{km}{hr}$=$50{\times}\frac{5}{18}=\frac{125}{9}ms^{-1}$, t=$45sec$.

Since, the car is brought to rest, therefore v=0

Using the formula, v=u+at where u is the initial velocity and v is the final velocity.

⇒$0=\frac{125}{9}+a(45)$

⇒$-\frac{125}{9}=a(45)$

⇒$a=-\frac{125}{9{\times}45}$

⇒$a=-0.30 ms^{-2}$

Thus, the retardation will be= $0.30 ms^{-2}$