Question

what is the roots of the quadratic2x2+6=-7x​

Answer 1

Answer:

plz mark as brainleast ......

Answer 2

Answer:

-3/2 and -2

Step-by-step explanation:

Given equation is $2x^{2} + 6 = -7x$

⇒ $2x^{2} + 7x + 6 = 0$

The given equation is of the form $ax^{2} + bx + c = 0$

where a, b, c are coefficients and $a \neq 0$

The roots can be obtained by multiplying the coefficients a and c, and finding the factors for the product and writing coefficient b as the sum of the product of factors.

Here a = 2, b = 7 and c = 6

⇒ a×c = 2×6 = 12

The factors for 12 are 1, 2, 3, 4, 6 and 12.

The given equation can be rewritten as, $2x^{2} + 4x + 3x + 6 = 0$

Now we need to group the similar terms.

⇒ $2x(x + 2) 3(x+2) = 0$

⇒ $(2x+3) (x+2) = 0$

Now equate both the terms to zero.

⇒ $2x+3 = 0$            ⇒ $x+2 = 0$

⇒ $x = -\frac{3}{2}$                 ⇒ $x = -2$

Therefore, the roots of the given quadratic equation are $-\frac{3}{2} and -2$