What is the self inductance of a coil when a change of current from 0 to 2 a in 0.05 s induces an emf of 40 v in i?
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e=Ldi/dt
40=L(2/0.05)
40*0.05/2=L
L=20*0.05=1H
40=L(2/0.05)
40*0.05/2=L
L=20*0.05=1H
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