Question

What is the simplified form of the following expression? Assume x≥0 and y≥0

Answer 1

in the first bracket we have
14ac(4^√ab²)
now on solving

we have 7ac4^√ab²

Answer 2

Answer:

The simplified form of the given expression $14(\sqrt[4]{a^5b^2c^4})-7ac\sqrt[4]{ab^2}$ is $7ac(\sqrt[4]{ab^2})$.

Step-by-step explanation:

Consider the given expression,

$14(\sqrt[4]{a^5b^2c^4})-7ac\sqrt[4]{ab^2}$   ...(A)

now, we have to simplify it , so lets simplify the first term,

$14(\sqrt[4]{a^5b^2c^4})=14(\sqrt[4]{aa^4b^2c^4})=14ac(\sqrt[4]{ab^2})$

Put the above value of $14(\sqrt[4]{a^5b^2c^4})$ in (A) , we get

$14(\sqrt[4]{a^5b^2c^4})-7ac\sqrt[4]{ab^2}=14ac(\sqrt[4]{ab^2})-7ac\sqrt[4]{ab^2}$

Taking $7ac(\sqrt[4]{ab^2})$ common,

$14ac(\sqrt[4]{ab^2})-7ac\sqrt[4]{ab^2}=7ac(\sqrt[4]{ab^2})[2-1]=7ac(\sqrt[4]{ab^2})$

Thus, the simplified form of the given expression $14(\sqrt[4]{a^5b^2c^4})-7ac\sqrt[4]{ab^2}$ is $7ac(\sqrt[4]{ab^2})$.