Question

What is the size of an image if it is 2 cm high placed in 10 cm from a concave mirror producing an image distance of 10 cm

Answer 1

Explanation:

Given that,

Focal length f=

2

R

Radius of curvature R=30

Object distance u=10cm

Height of object h

o

=2cm

From the mirror formula,

f

1

=

v

1

+

u

1

−

v

1

=

u

1

−

f

1

−

v

1

=

10

1

−

30

2

−

v

1

=

30

3−2

v=−30cm

Now, the magnification is

m=

u

−v

m=

10

30

m=3

Now, the height of image

m=

h

o

h

i

3=

2

h

i

h

i

=6cm

Hence, the image distance is −30 cm, height of image is 6 cm and magnification is 3

Answer 2

Explanation:

if if the size of image is 2 cm height and itbase is 10 centimetre as in concave mirror or is image is highly produce in days of 10 centimetre in in other mirror then the real picture of an image is 2 cm only then we have to change the mirror and we have to see that what is the explanation

have be done

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