What is the smallest four-digit number which when divided by 6, leaves a remainder of 5 and when divided by 5 leaves a reminder of 3?
Answers
Answered by
1
the smallest 4-digit number is = 1013
1 . For easy method you can do it in python.
CODE =
#include <studio.h>
int main ( ) {
int i = 1000;
Do {I++;} while (!(i%6==5 && i%5==3));
Print f ("%d\h";I);
} // result : 1013
2 . let a no be x
x = 6a+5 = 5b+3
6a+2= 5b
a+2 = 5b'
b' = 1 ,a =3,b=4
x = 23+30000
30×33 = 990 → 1013
1 . For easy method you can do it in python.
CODE =
#include <studio.h>
int main ( ) {
int i = 1000;
Do {I++;} while (!(i%6==5 && i%5==3));
Print f ("%d\h";I);
} // result : 1013
2 . let a no be x
x = 6a+5 = 5b+3
6a+2= 5b
a+2 = 5b'
b' = 1 ,a =3,b=4
x = 23+30000
30×33 = 990 → 1013
Answered by
0
Answer: it is 1013 buddy
Hope it helps
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