Math, asked by jadalajanardhan, 1 year ago

What is the smallest number by which 1328 may be multiplied so that the product is a perfect cube

Answers

Answered by pulakmath007
1

SOLUTION

TO DETERMINE

The smallest number by which 1328 may be multiplied so that the product is a perfect cube

EVALUATION

 \sf{1328}

 =  \sf{2 \times 2 \times 2 \times 2 \times 83}

 =  \sf{ {2}^{3}   \times 2 \times 83}

In order to get the smallest number by which 1328 may be multiplied so that the product is perfect cube is

 =  \sf{ {2}^{2} \times  {83}^{2}  }

So the transformed number is

 =  \sf{ {2}^{3}  \times  {2}^{3} \times  {83}^{3}  }

Hence the required number

 =  \sf{ {2}^{2} \times  {83}^{2}  }

 = 27556

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