Question

what is the smallest number by which 46080 must be divided to get a perfect square also find the square root of the perfect squares so obtained​

Answer 1

Step-by-step explanation:

prime factorization of 46080=

${2}^{10} \times {3}^{2} \times 5$

Now, 5 is not in pair, so we must divide the given no. with 5

After dividing with 5 we left with

${2}^{10} \times {3}^{2}$

so, square root of this is,

${2}^{5} \times {3}$

= 96

_________________

Amrit

Answer 2

Answer:

by prime factorisation

 2   46080

 2   23040

 2   11520

 2   5760               2x2x2x2x2x2x2x2x2x2x3x3x5

 2   2880               as 5 is not in the group of 2 so we must divide 5

 2   1440                 to get a perfect  square.

 2   720                  46080/5

 2   360                  √9216 = 96

 2   180

 2    90

 3    45

 3     15

 5      5

          1