What is the smallest number by which 8640 must be divided so that the quotient is a perfect cube step by step answer in page
Answers
Answered by
0
Firstly factor of 8640 is 2*2*2*2*2*2*3*3*3*5.
In cube we do the pair of three each. Then 5 is left that's why we have to divide 8640 by 5 then we get 1728.
In cube we do the pair of three each. Then 5 is left that's why we have to divide 8640 by 5 then we get 1728.
Similar questions