What is the smallest number by which 8640 must be divided so that the quotient is a perfect cube and find cube of the number so obtained
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8640=2×2×2×2×2×2×3×3×3×5
5 occurs as a prime number only once.
Hence, 5 is the smallest number by which 8640 must be divided, so that the quotient is a perfect cube.
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Answer:
2 is the answer
Step-by-step explanation:
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