Question

What is the smallest number by which the following numbers must multiplied
that the products are perfect cube
1) 7803​

Answer 1

Step-by-step explanation:

Given Number = 7803

…3 | 7803

…3 | 2601

…3 | 867

..17 | 279

……| 17

7803 = 3 × 3 × 3 × 17 × 17

In Exponential form,

7803 = 3³ × 17²

Here 17 is the number that is not having 3 as its power.

•°• The Number 17 is to be multiplied with 7803 to make it a perfect cube.

•°• Required least Number = 17.

Hope this is useful for u

pls mark me as brainliest

Answer 2

Answer:

Smallest number =17

Step-by-step explanation:

Factors of 7803=3*3*3*17*17

So 17 is the smallest number to make 7803 a perfect cube.

Pls mark a brainliest