Question

what is the smallest number that divisible by 18 24 54​

Answer 1

Answer:

2 is divisible by 18,24,54.

2×9=18

2×12=24

2×27=54.

Answer 2

Step-by-step explanation:

LCM OF 18 , 24 , 52

Let's factorize,

24 = 2x2x2x3

36 = 2x2x3x3

54 = 2x3x3x3

The smallest number divisible by all 24, 36, 54 is:

LCM(24, 36, 54) = 216

Thus, to get 5 as remainder, we need to add 5 to 216.

(as 216 is the smallest number which gives remainder 0 when divided by 24 or 36 or 54)

216 + 5 = 221

For 12, 221 gives 18 as quotient and 5 as remainder

For 36, 221 gives 6 as quotient and 5 as remainder

For 54, 221 gives 4 as quotient and 5 as remainder

Hence, 221 is required number.