Math, asked by josephshashi12177, 4 months ago

What is the smallest number that should
be ( i ) added to and ( ii ) subtracted from
483 to get it divisible by 9.

Answers

Answered by DarkGhoat18

2

Answer:

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Answered by alyssa07

3

Answer:

Add 3 to 483 to make it divisible by 9( 483+3=486÷9=54)
Subtract 6 from 483 to make it divisible by 9(483-6=477÷9=53)

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