What is the smallest number that should
be ( i ) added to and ( ii ) subtracted from
483 to get it divisible by 9.
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2
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Answered by
3
Answer:
- Add 3 to 483 to make it divisible by 9( 483+3=486÷9=54)
- Subtract 6 from 483 to make it divisible by 9(483-6=477÷9=53)
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