Question

what is the smallest number that when divided by 35,56,91 leaves a remainder of 7 in each case?

Answer 1

Take LCM of 35,56,91:

35=7x5

56=2x2x2x7

91=13x7

LCM of 35,56,91=2x2x2x7x5x13=3640

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

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