What is the smallest number that when divided by 35,56 and 91 leaves remainder of 7 in each case?
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Step-by-step explanation:
The smallest number which when divided by 35, 56 and 91 = LCM(35,56,91)
35=5×7
56=2^3×7
91=7×13
LCM=2^3×5×7×13=3640
The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647
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