Question

What is the smallest number that when divided by 35,56 and 91 leaves remainder of 7 in each case? ​

Answer 1

Step-by-step explanation:

The smallest number which when divided by 35, 56 and 91 = LCM(35,56,91)

35=5×7

56=2^3×7

91=7×13

LCM=2^3×5×7×13=3640

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647

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