what is the smallest number that when divided by 35,56 and 91 leaves remainders of 7 in each case?
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Answered by
17
First we subtract the 7 from each no.
35-7= 28= 7×2×2
56-7= 49=7×7
91-7= 84= 2×2×3×7
Smallest no is HCF of these no. = 7×2= 14.
35-7= 28= 7×2×2
56-7= 49=7×7
91-7= 84= 2×2×3×7
Smallest no is HCF of these no. = 7×2= 14.
sunshine30:
but the answer is 3647
Your answer is wrong.
I have checked in the book
Name the book.
rd sharma
Which class
Answered by
10
hopeing this answer is helpful.
pls mark me as brainliest.
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