Math, asked by sunshine30, 16 days ago

what is the smallest number that when divided by 35,56 and 91 leaves remainders of 7 in each case?


Answered by kuldeep147
First we subtract the 7 from each no.

35-7= 28= 7×2×2

56-7= 49=7×7

91-7= 84= 2×2×3×7

Smallest no is HCF of these no. = 7×2= 14.

sunshine30: but the answer is 3647
kuldeep147: Your answer is wrong.
sunshine30: I have checked in the book
kuldeep147: Name the book.
sunshine30: rd sharma
kuldeep147: Which class
Answered by jemijohn2005

hopeing this answer is helpful.

pls mark me as brainliest.

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