Question

what is the smallest number which can be divided by 20,28,36 and leaves 4 as a remainder​

Answer 1

Answer:

5, 20, 25, 35, 40

∣

24,5,7,8

∣

22,5,7,4

∣

1,5,7,2

∴L.C.M.=5×2×2×5×7×2=1400

20−14=25−19=35−29

=40−34=6

∴ required number

=LCM−6

=1400−6

=1394.

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