What is the smallest number which should be i)added to and ii) subtracted from a) 12531 to get a number divisible by 4=?
Answers
Answer:
We will divide the number 10003 by 11 to find the remainder. The remainder is the number which when subtracted from the given number will give us a number which is exactly divisible by 11. Therefore, the remainder is the required number.
Step-by-step explanation:
The number 10003 is not divisible by 11.
The number 10003 is not divisible by 11.We have to find a number that we can subtract from 10003 so that the number is divisible by 11.
The number 10003 is not divisible by 11.We have to find a number that we can subtract from 10003 so that the number is divisible by 11.We will first divide the number 10003 by 11 and find its remainder.
Hence, we can say that the remainder is 4 and the quotient is 909.
Hence, we can say that the remainder is 4 and the quotient is 909.If we will subtract the remainder from 10003, we will get a number that is exactly divisible by 11.
Hence, we can say that the remainder is 4 and the quotient is 909.If we will subtract the remainder from 10003, we will get a number that is exactly divisible by 11.Therefore, 10003−4=999910003−4=9999
Hence, we can say that the remainder is 4 and the quotient is 909.If we will subtract the remainder from 10003, we will get a number that is exactly divisible by 11.Therefore, 10003−4=999910003−4=9999Thus, the smallest number which is subtracted from 10003 so that it is exactly divisible by 11 is 4.
Given:
What is the smallest number which should be i)added to and ii) subtracted from a) 12531 to get a number divisible by 4=?
Solution:
Know that a number is always divisible by 4 if the last three digits of the number is divisible by 4.
Take last three digits of 12531 and divide by 4,
on dividing 531 by 4, the remainder will be 3.
Therefore add 1 or subtracted 3 from 12531 to get a number divisible by 4.
Hence, 1 should be added or 3 should be subtracted from 12531 to get a number divisible by 4.