What is the smallest number which when decreased by 8 is divisible by 21, 27, 33, and 55?
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In order to calculate smallest number divisible by 21,27,33,55 you first have to find LCM of these 4 no. Answer: The required number which when decreased by 8 is divisible by 21, 27, 33, and 55 is 10403
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