Math, asked by SwatiMandade, 8 months ago


What is the smallest number which when diminished by 7, is divisible by 12, 16, 21 and 28?
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Answers

Answered by jameshul471
5

Answer:

Answer Expert Verified

First find the smallest number divisible by 12,16,18,21 and 28. It is the LCM of these numbers. So the number will be 1008+7 = 1015. So the required number is 1015.

Step-by-step explanation:

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Answered by hdtus
0

Step-by-step explanation:

first find the LCM of 12 16 21 28 = 336

now multiply LCM by 7 is 336×7 = 2352

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