Question

What is the smallest positive integer which should be multiplied with 6n

(where n is a natural number) so

that it ends with the digit 0?​

Answer 1

Answer:

5 should be multiplied

Step-by-step explanation:

6n=(2*3)n

6n= (2*5*3)n

10*3n

(30)^n

Answer 2

The answer is 5.

• In the table of 6, multiplication with 5 gives the first number that ends with a zero in the one's place. Thus, it is the smallest positive integer that, when multiplied by 6n, gives a number ending in zero.

• If n is a natural number, then it will not be zero. It will be any number from 1 to infinity.

• However, the position of the zero in the one's place will remain intact because any number multiplied by zero answers zero.

• 6n × 5 = 30n will be the equation.

#SPJ2