What is the smallest resistance can be obtained by combination of n resistor each resistance is r
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Answer:
n/r (parallel)
Explanation:
in parallel,resistance = 1/R1 + 1/R2 +....1/Rn----> resistance is lesser in this case .
In series, resistance= R1+ R2 +....Rn
Since, each resistance is r,
Net resistance [parallel]= 1/r + 1/r +....(n times).
= n/r
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