Question

What is the solution for this 3r² - 7r + 4 = 0 ?

Answer 1

$3 {r}^{2} - 7r + 4 = 0 \\ 3 {r}^{2} - 4r - 3r + 4 = 0 \\ r(3 r - 4) - 1(3r + 4) = 0 \\ (3r - 4)(r - 1) = 0 \\ if \: 3r - 4 = 0 \\ r = \frac{4}{3} \\ if \: r - 1 = 0 \\ r = 1$
Heyy friend your answer is here

Answer 2

$(7 + \sqrt{ {7}^{2} - 4 \times 3 \times 4} ) \div 2 \times 3$
r=4/3
$(7 - \sqrt{ {7}^{2} - 4 \times 3 \times 4 } ) \div 2 \times 3$
r=1
answer is 4/3 or 1