Question

The molarity of 900 g water is

Answer 1

Density of water = 1g/mL
Volume of 900g of water = 900mL
Moles of water = Given massMolecular mass = 90018 = 50mol
Molarity of water = 50900×1000 = 55.55M

Answer 2

Answer : The morality of 900 g of water is, 55.5 M

Solution : Given,

Density of water = 1 g/ml

Mass of water = 900 g

First we have to calculate the volume of water.

$\text{Volume of water}=\frac{\text{Mass of water}}{\text{Density of water}}=\frac{900g}{1g/ml}=900ml$

Volume of water = 900 ml

Now we have to calculate the moles of water.

$\text{Moles of water}=\frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{900g}{18g/mole}=50mole$

Now we have to calculate the molarity of water.

$\text{Molarity of water}=\frac{\text{Moles of water}}{\text{Volume of water in liters}}\times 1000=\frac{50mole}{900ml}\times 1000=55.5mole/L=55.5M$

Therefore, the morality of 900 g of water is, 55.5 M