What is the solution of log2x − 3125 = 3?
Answers
Answered by
10
Answer:
log₂ᵪ₋₃(125) = 3
take antilog₂ᵪ₋₃ of both sides
125 = (2x-3)³
5³ = (2x-3)³
5 = 2x-3
x = 4
Answered by
1
Answer:
log₂ᵪ₋₃(125) = 3
take antilog₂ᵪ₋₃ of both sides
125 = (2x-3)³
5³ = (2x-3)³
5 = 2x-3
x = 4
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