Math, asked by ashnaansari2121, 6 months ago

what is the solution of this answer​

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Answered by LaeeqAhmed
0

 \frac{ {a}^{ - 1} }{ {a}^{ - 1} +  {b}^{ - 1}  }   +  \frac{ {a}^{ - 1} }{ {a}^{ - 1} +  {b}^{ - 1}  }

 \implies  \frac{ (\frac{1}{a}) }{( \frac{1}{a} ) + ( \frac{1}{b}) }   +  \frac{ (\frac{1}{a}) }{( \frac{1}{a} ) + ( \frac{1}{b}) }

 \implies \frac{ (\frac{1}{a}) }{( \frac{a + b}{ab} )  }   +  \frac{ (\frac{1}{a}) }{( \frac{a + b}{ab} )  }

 \implies \frac{ (b)}{( a + b)  }   +  \frac{ (b) }{( {a +  b} )  }

\implies \frac{2 (b)}{( a + b)  }

\implies \frac{2 (b)}{( a + b)  }  \times  \frac{(a - b)}{(a - b)}

\implies \frac{2 (ab) - 2 {b}^{2} }{ a ^{2}   -  b {}^{2}  }

\implies \frac{ - 2 ( - ab  +  {b}^{2}) }{ a ^{2}   -  b {}^{2}  }

\implies \frac{  2 (  {b}^{2} - ab  ) }{ {b}^{2} -   a ^{2}     }

 { \boxed{\color{orange}\therefore \frac{  2   {b}^{2} - 2ab   }{ {b}^{2} -   a ^{2}     }  }}

HOPE THAT HELPS!!!

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