what is the solution of this question no 3
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you have to find here that maximum no. of columns in which they march.
so, you have to find h.c.f:-
616=32×19+8
32=8×4+0
so hcf is 8
hence, 8 no. of columns
so, you have to find h.c.f:-
616=32×19+8
32=8×4+0
so hcf is 8
hence, 8 no. of columns
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