Question

what is the solution set for x if (x - 2) =√10x-19​

Answer 1

a=19x-2−2x ;     x≠ 2, x≠ 0, x≠ 1+ii, x≠ 1−ii

Answer 2

Answer:

x-2=√10x-19

x-√10x=-19+2

x(1-√10)=-17

x=-17/1-√10. परिमेयीकरण

x=17/1-√10×1+√10/1+√10

x=-17(1+√10)/-9

x=17(1+√10)/9