Question

What is the solution to this system of linear equations? 2a – 3c = –6 a + 2c = 11

Answer 1

a=5/2 & c=-2 see it by tillting it

Answer 2

Answer:

The solutions of the equations are a = 3 and c = 4 .

Step-by-step explanation:

As given

2a – 3c = –6

a + 2c = 11

Multiply a + 2c = 11 by 2 and subtrated from  2a – 3c = –6 .

2a - 2a -3c -4c = -6 -22

-7c = -28

$c = \frac{-28}{-7}$

c = 4

Putting the value of c in the equation a + 2c = 11 .

a + 2 × 4 = 11

a + 8 = 11

a = 11 - 8

a = 3

Therefore the solutions of the equations are a = 3 and c = 4 .