Question

What is the sound level in dB for a sound whose intensity is 5.0 x 10-6 watts/m2?

Answer 1

use the formula L loudness= 10 log I/I₀

as intensity level in db is nothing but loudness.

Answer 2

Given :

Intensity of sound , $I=5\times 10^{-6}\ watts/m^2$ .

To Find :

The sound level in dB .

Solution :

The sound level in dB is given as :

$b=10\times log(\dfrac{I}{I_o})$        .....( 1 )

Here , $I_o$ is a constant and given as $I_o=10^{-12}\ W/m^2$ .

Putting value of I and $I_o$ in equation 1 .

We get :

$b=10\times log(\dfrac{5\times 10^{-6}}{10^{-12}})\\\\b=10\times 6.7\\b=67\ dB$

Therefore , the sound level in dB is 67 dB .

Learn More :

Sound Intensity

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