Question

What is the specific heat of a metal if 50 cal of heat is needed to raise 6 kg of metal from 20°C to 62°C​

Answer 1

Specific heat of the metal will be $c=0.1587cal/^{\circ}C$

Explanation:

We have given heat $Q=40cal$

Mass of the metal is given m = 6 kg

It is given that temperature of meta is increases from $20^{\circ}C\ to\ 62^{\circ}C$

So increase in temperature $\Delta T=62-20=42^{\circ}C$

We have to find the specific heat of the metal

We know that energy required to increase the temperature of any body is given by  $Q=mc\Delta T$, here c is specific heat of metal

So $40=6\times c\times 42$

$c=0.1587cal/^{\circ}C$

So specific heat of the metal will be $c=0.1587cal/^{\circ}C$

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