Question

What is the specific heat of a metal if 50 cal of heat is needed to raise 6 kg of metal from 20°C to 62°C​

Answer 1

Specific heat of the metal will be c = 0.1984 J/kg°C

Explanation:

We have given heat required to increase the temperature of metal is 50 cal

Mass of the metal m = 6 kg

Temperature is increases from 20°C to 62°C

So increase in temperature $\Delta T$ = 62°C-20°C = 42°C

We know that heat need top increase the temperature is given by

$Q=mc\Delta T$, here m is the mass, c is the specific heat of the metal and $\Delta T$ is increase in temperature

So 50 = 6×c×42

c = 0.1984 J/kg°C

So specific heat of the metal will be c = 0.1984 J/kg°C

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Answer 2

The specific heat of a metal is $c=0.83\ J/kg^{\circ}C$.

Explanation:

Given that,

Heat produced, Q = 50 cal = 209.2 Joules

Mass, m = 6 kg

Initial temperature, $T_i=20^{\circ}$

Final temperature, $T_f=62^{\circ}$

To find,

The specific heat of a metal.

Solution,

The specific heat in terms of heat is given by :

$Q=mc\Delta T$

$c=\dfrac{Q}{m\Delta T}$

$c=\dfrac{209.2}{6\times (62-20)}$

$c=0.83\ J/kg^{\circ}C$

So, the specific heat of a metal is $c=0.83\ J/kg^{\circ}C$.

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