Question

What is the speed of an apple dropped from a tree 1.5 second what distance will it cover during this time take G is equal to 10 M per second square

Answer 1

Initial speed of the apple (u) = 0 m/s

Time taken (t)= 1.5 seconds

Acceleration due to gravity (g) = 10 m/s^2

Let the distance covered by the apple in 1.5 seconds be s.

Now, using the second equation of motion:

$s = ut + \frac{1}{2}a t^2$

$s = 0 \times 1.5 + \frac{1}{2} \times 10 \times 1.5 \times 1.5$

s = 11.25 meters

Hence, the distance covered by the apple in 1.5 seconds is 11.25 meters.

Answer 2

<<<<<<ANSWER>>>>>>

v= u±at

u, Initial velocity of apple=0

a, acceleration due to gravity=10 m/s²

t, time = 1.5 second

v, speed of apple=?

v=0±10×1.5=15

>Speed after 1.5 sec =15m/s

Distance covered by apple:-

s=ut±1/2at²

u=0; t=1.5sec ;a=10m/s²

s=0×1.5±1/2×10×(1.5)²=0±1/2 ×10×2.25=11.25

Distance covered by the apple=11.25m

✨️❤✨️✨️❤✨️✨️✨️❤✨️✨️✨️✨️❤