What is the speed of an Apple dropped from a tree after 1•5second?rwhat distance will it cover during this time ?Take g=10m/ssquare
Answers
Answered by
5
Hey User
Answer will be 11.25m
as acceleration is constant i.e g
by Second Equation of Motion
s = ut + 1/2at²
as initially u = 0 (dropped)
s = 1/2at²
s = 1/2×10×(1.5)²
s = 11.25m
Answer will be 11.25m
as acceleration is constant i.e g
by Second Equation of Motion
s = ut + 1/2at²
as initially u = 0 (dropped)
s = 1/2at²
s = 1/2×10×(1.5)²
s = 11.25m
Answered by
4
v = u + at
= 0 + (9.8 m/s² × 1.5 s)
= 14.7 m/s
Speed after 1.5 seconds is 14.7 m/s
S = ut + 0.5at²
= 0 + (0.5 × 9.8 m/s² × (1.5 s)²)
= 11.025 m
Distance covered during this time is 11.025 m
= 0 + (9.8 m/s² × 1.5 s)
= 14.7 m/s
Speed after 1.5 seconds is 14.7 m/s
S = ut + 0.5at²
= 0 + (0.5 × 9.8 m/s² × (1.5 s)²)
= 11.025 m
Distance covered during this time is 11.025 m
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