Question

What is the speed of an apple dropped from a tree after 1.5 second .? What distance will it covers during this time

Answer 1

v = u + at
= 0 + (9.8 m/s² × 1.5 s)
= 14.7 m/s
Speed after 1.5 seconds is 14.7 m/s

S = ut + 0.5at²
= 0 + (0.5 × 9.8 m/s² × (1.5 s)²)
= 11.025 m
Distance travelled during this time is 11.025 m

Answer 2

Answer:

v= u±at

u, Initial velocity of apple=0

a, acceleration due to gravity=10 m/s²

t, time = 1.5 second

v, speed of apple=?

v=0±10×1.5=15

>Speed after 1.5 sec =15m/s

Distance covered by apple:-

s=ut±1/2at²

u=0; t=1.5sec ;a=10m/s²

s=0×1.5±1/2×10×(1.5)²=0±1/2 ×10×2.25=11.25

Distance covered by the apple=11.25m

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