Question

What is the speed of an apple dropped from a tree after 1.5 s? what distance will it cover during this time? Take g=10 M/S

Answer 1

Let the velocity by which the Apple is moving me v ms.


Initial Velocity of the speed(u) = 0

Time taken by the Apple to fall = 1.5 s.


Using the First Equation of the motion,

v - u = at

∴ v - 0 = 10 × 1.5

⇒ v = 15 m/s.



Hence, the velocity of the Apple is 15 m/s.

Answer 2

Answer:

v= u±at

u, Initial velocity of apple=0

a, acceleration due to gravity=10 m/s²

t, time = 1.5 second

v, speed of apple=?

v=0±10×1.5=15

>Speed after 1.5 sec =15m/s

Distance covered by apple:-

s=ut±1/2at²

u=0; t=1.5sec ;a=10m/s²

s=0×1.5±1/2×10×(1.5)²=0±1/2 ×10×2.25=11.25

Distance covered by the apple=11.25m

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