what is the sqare root of 19881
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heya...
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Here is your answer. ....
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HEY .....(^_^)
√3 + √2 / √3 - √2
= (√3 + √2 / √3 - √2 ) × ( √3 + √2 / √3 + √2)
= (√3 + √2)^2 / (√3)^2 - (√2)^2
= [ (√3)^2 + (√2)^2 + 2×√3×√2 ] / 3-2
= 3 + 2 + 2√6 / 1
= 5 + 2√6
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