Question

what is the sqaure root of -5+12iota

Answer 1

let z=-5+12i=|z|(cosa+isina)=|z|(e^ia)

where |z|=√(5^2+12^2)=13

and a=arccos(-5/13)

required √z = √13(e^(i(a/2)))

then a/2=1/2*arccos(-5/13)=arccos(3/√13)

so √z=√13(cos(a/2)+isin(a/2))=3+√4i

Answer 2

Answer:

Finding the square root

Step-by-step explanation:

-5+12= 12-5=7

7 ÷ 2 =3.5

The answer is 3.5